5.6 Solving Optimization Problems Homework Review

Second derivative: ( A''(W) = -4 < 0 ), so it is concave down → maximum. Answer: The field should be 120 m (parallel to river) by 60 m (perpendicular). Maximum area = ( 120 \times 60 = 7200 ) m².

( S(0) = 9 ) → ( D = 3 ). ( S(\pm 1.581) = (1.581)^4 - 5(1.581)^2 + 9 \approx 6.25 - 12.5 + 9 = 2.75 ) → ( D \approx 1.658 ). 5.6 Solving Optimization Problems Homework

that’s giving you trouble, or should we walk through a full example of the box-cutting problem? Second derivative: ( A''(W) = -4 &lt; 0

If you are working through your , this guide will break down the essential workflow and common problem types you’ll encounter. The 5-Step Framework for Success ( S(0) = 9 ) → ( D = 3 )

A farmer has 240 meters of fencing. He wants to enclose a rectangular field along a river, so he only needs fencing on three sides (the river acts as the fourth side). What dimensions maximize the area?

Keep practicing, draw every diagram, and never skip the justification step. As you work through your worksheet tonight, remember: each derivative you set to zero is a step toward the optimal solution.